Chemistry - Solid State Question with Solution | TestHub

ChemistrySolid StateGeneralEasy2 minPYQ_2020

ChemistryEasynumerical

Edge length of face centred cubic unit cell of an ionic solid AB is 508 pm. If the radius of $A^{+}$ ion is 110 pm, the radius of $B^{-}$ ion in pm will be

Answer:

144.00

Solution:

Edge length $= 2 r_{A^{+}} + 2 r_{B^{-}}$
$508 = 2 \times 110 + 2 r_{B^{-}}$
$2 r_{B^{-}} = 508 - 220 = 288$
$r_{B^{-}} = 144$ pm

Stream:JEESubject:ChemistryTopic:Solid StateSubtopic:General

⏱ 2mℹ️ Source: PYQ_2020

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