Chemistry - Solid State Question with Solution | TestHub

According to molecular orbital theory, outer configuration for $$\left[{\mathrm{C}}_2\right]={\mathrm{C}}_{12}\to \pi p_x^2=\pi p_y^2$$ Thus, is diamagnetic in nature. $$\left[{\mathrm{B}}_2\right]={\mathrm{B}}_{10}->\pi p_x^1=\pi p_y^1$$ Thus, is paramagnetic in nature.