Chemistry - Salt Analysis Question with Solution | TestHub

ChemistrySalt AnalysisTEST OF CATIONS, Group 3, 4, 5, 6, 0Medium2 minQB
ChemistryMediumnumerical
Passage / Comprehension

A metal ion (M) solution neither form precipitate with dilute HCl, nor with in acidified aqueous solutions but produces 9 gram black precipitate(X) in alkaline medium with . Black precipitate X is completely dissolved in aqua regia. The aqueous solution obtained after treatment with aqua regia is neutralised with ammonium hydroxide and then acidified with acetic acid and filtered. In the filtrate strong solution of potassium nitrite is added, which gives yellow precipitate. In the last reaction, a paramagnetic gas is released as a byproduct.

Calculate the number of moles of paramagnetic gas evolved in the last reaction.

Given molar mass (gm/mol.) ⇒ H = 1 , N = 14 , O = 16 , S = 32 , Cl = 35.5 , K = 39 , Co = 58 Zn = 65 , Cu = 63.5 , Mn = 55 , Fe = 56 , Sn = 119 , Pb = 207 , Ni = 58.6 , Cd = 112.5 , Hg = 200

Answer:
0.10
Solution:

 

 

Stream:JEESubject:ChemistryTopic:Salt AnalysisSubtopic:TEST OF CATIONS, Group 3, 4, 5, 6, 0
2mℹ️ Source: QB

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