Chemistry - Salt Analysis Question with Solution | TestHub

ChemistrySalt AnalysisTEST OF CATIONS Dry Test, Group Analysis, Group 1,2Medium2 minQB
ChemistryMediuminteger

Mark by ✓ symbol in a corresponding window those ions for which the assertions written on the left side of the table, are true and calculate number of total blank windows after filling table.

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Answer:
13
Solution:

* Assertion 1 (White ppt with NaOH): Only forms a white precipitate (). (1 match)

* Assertion 2 (Black ppt with ): (), (), and () form black precipitates. (3 matches)

* Assertion 3 (Colored solution with excess KCN): Only forms a colored (yellowish) solution of . (1 match)

* Assertion 4 (Insoluble with excess ): and form insoluble precipitates, while and dissolve. (2 matches)

* Assertion 5 (Brownish color with excess KI): and oxidize to release brown iodine (). (2 matches)

 

* Assertion 6 (Redox change with excess ): All four cations (, , , ) undergo chemical or redox-associated transformations. (4 matches)

 

Total number of checkmarks = .

Stream:JEESubject:ChemistryTopic:Salt AnalysisSubtopic:TEST OF CATIONS Dry Test, Group Analysis, Group 1,2
⏱ 2mℹ️ Source: QB

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