Chemistry - Salt Analysis Question with Solution | TestHub
ChemistrySalt AnalysisTEST OF CATIONS Dry Test, Group Analysis, Group 1,2Medium2 minQB
ChemistryMediumsingle choice
Passage / Comprehension
The basic radical are detected by various reagent through precipitation reaction and some of the precipitate soluble in excess of reagent.
Which of the following cation does not form soluble complex with excess of NaOH ?
Options:
Answer:
C
Solution:
In cation analysis, some metal hydroxide precipitates dissolve in excess NaOH due to the formation of soluble complexes (amphoteric nature).
Cr³⁺, Zn²⁺, and Sn²⁺ form soluble complexes with excess NaOH.
Cu²⁺ forms Cu(OH)₂ precipitate, which does not dissolve in excess NaOH.
Therefore, Cu²⁺ does not form a soluble complex with excess NaOH.
Correct Answer: (C) Cu²⁺
Stream:JEESubject:ChemistryTopic:Salt AnalysisSubtopic:TEST OF CATIONS Dry Test, Group Analysis, Group 1,2
⏱ 2mℹ️ Source: QB
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