Chemistry - Salt Analysis Question with Solution | TestHub
A mixture of two salts, S₁ and S₂ of the same metal, produces the following observations:
1. An aqueous solution of in dilute HCl produces a white precipitate with BaCl₂, which is insoluble in dilute HNO₃.
2. The mixture is insoluble in water but dissolves in dilute HCl with the evolution of a colourless, odourless gas (G), which turns lime water milky.
3. The solution of in dilute HCl does not precipitate with H₂S, but yields a white precipitate with NaOH, which dissolves in excess aqueous NaOH.
The salts S₁ and S₂ are:
Options:
Answer:
Solution:
Sulfate detection: Formation of a white precipitate with BaCl₂ insoluble in dilute HNO₃ confirms the presence of SO₄²⁻ ions.
Carbonate detection: Evolution of a colorless, odorless gas (CO₂) that turns lime water milky confirms the presence of CO₃²⁻ ions.
Cation separation: Lack of precipitation with H₂S in an acidic medium rules out Group II cations like Pb²⁺.
Cation confirmation: The formation of a white precipitate with NaOH that dissolves in excess confirms amphoteric Zn²⁺ ions.
Conclusion: Therefore, the two salts of the same metal are ZnSO₄ and ZnCO₃ (Option D).
