Chemistry - Salt Analysis Question with Solution | TestHub
Match the following :-
List - I (Pair of Ions) | List - II (Reagent which can be used to precipitate only one ion from given pair of ions) |
|---|---|
(A) | (P) |
(B) | (Q) both |
(C) | (R) dil HCl only |
(D) | (S) Excess NaOH |
| (T)
|
Options:
Answer:
Solution:
(A) Cu²⁺, Zn²⁺: H₂S/HCl (Q) precipitates only CuS, while excess NaOH (S) precipitates Cu(OH)₂ but dissolves Zn²⁺ as a soluble zincate complex.
(B) Zn²⁺, Ba²⁺: Na₂SO₄ (T) precipitates only BaSO₄; ZnSO₄ remains soluble.
(C) Cu²⁺, Ag⁺: Dilute HCl (R) precipitates only AgCl, and Na₂SO₄ (T) precipitates Ag₂SO₄ while CuSO₄ is highly soluble.
(D) K⁺, Sr²⁺: (NH₄)₂CO₃ (P) and Na₂SO₄ (T) both precipitate Sr²⁺ (as carbonate and sulfate respectively), whereas K⁺ salts are always soluble.