Chemistry - Salt Analysis Question with Solution | TestHub
An aqueous solution of salt (P) gives white precipitate with Barium chloride solution which is insoluble in dilute HCl & dilute . When ammonia (aq) is added to the aqueous solution of salt (P) blue precipitate is obtained which dissolves in excess ammonia producing deep blue colouration due to formation complex (Q). With KCN, (P) gives first a yellow precipitate which quickly decomposes to white precipitate along with liberating highly poisonous gas (R). (R) on hydrogenation produces (S) which gives yellowish orange coloured complex (T) with .
Which of the following options is correct with respect to P, Q, R, S and T.
Options:
Answer:
Solution:
The white precipitate with BaCl₂ indicates SO₄²⁻, while the blue precipitate with NH₄OH confirms Cu²⁺. Excess ammonia forms the deep blue complex ²⁺ (Q). With KCN, Cu²⁺ liberates poisonous HCN (R), and hydrogenation of HCN gives methylamine (S), a bidentate ligand, which forms a yellowish-orange complex with CoCl₃. Therefore, option (B) is correct.
