Chemistry - Salt Analysis Question with Solution | TestHub
Consider information of given two solid salts i.e. salt A and salt B
SALT A - It exist as tetra hydrated form and freely soluble in water, aqueous solution of salt-A initially produce white precipitated (P1 ) with NaOH(aq.) , which is rapidly oxidizes on expose to air and becoming brown precipitate (P2 )
Another sample of aqueous salt-A produce white precipitate with BaCl2(aq.) + dil. HCl(aq.) . After separation of white precipitate resulting solution gives coloured sulphide precipitate (P3 ) with H 2S only in ammonical medium (NH4 OH + NH4Cl). precipitate (P3 ) is soluble in CH3 COOH(aq) .
SALT B - It is dissolve in water but when its aqueous solution is treated by KI dropwise initially black precipitate is form which is rapidly soluble in excess KI to gives orange solution-S1 . Another sample of aqueous solution of salt-B produces white precipitate (Q 1) with NaOH. White precipitate (Q1) produces orange brown solution-S2 with conc. H2O2 . Anion of salt-B produce white precipitate with lead nitrate which is soluble on addition of hot water.
Find total number of valence electron(s) in diatomic product obtained by the heating of brown precipitate with anion of SALT-B in acidic medium.
Answer:
Solution:
SALT A
SALT B
Brown ppt.
Orange brown solution