Choose the correct tests with respective observations. (A) CuSO 4 (acidified with acetic acid) + K 4 [ Fe ( CN ) 6 ] → Chocolate brown precipitate. (B) FeCl 3 + K 4 [ Fe ( CN ) 6 ] → Pruss

Question

Choose the correct tests with respective observations.
(A) $CuSO_{4}$ (acidified with acetic acid) $+ K_{4} [Fe (CN)_{6}] \to$ Chocolate brown precipitate.
(B) $FeCl_{3} + K_{4} [Fe (CN)_{6}] \to$ Prussian blue precipitate.
(C) $ZnCl_{2} + K_{4} [Fe (CN)_{6}]$ , neutralised with $NH_{4} OH$ $\to$ White or bluish white precipitate.
(D) $MgCl_{2} + K_{4} [Fe (CN)_{6}] \to$ Blue precipitate.
(E) $BaCl_{2} + K_{4} [Fe (CN)_{6}]$ , neutralised with NaOH $\to$ White precipitate.
Choose the correct answer from the options given below :

Options:

Answer:

C

Solution:

$2 CuSO_{4} + K_{4} [Fe (CN)_{6}] CH_{3} COOH (Chocolate brown ppt.) Cu_{2} [Fe (CN)_{6}] + 2 K_{2} SO_{4}$
$4 FeCl_{3} + 3 K_{4} [Fe (CN)_{6}] ⟶ (Prussian Blue ppt.) Fe_{4} [Fe (CN)_{6}]_{3} + 12 KCl$
$3 ZnCl_{4} + 2 K_{4} [Fe (CN)_{6}] NH_{4} OH (White or bluish white ppt.) K_{2} Zn_{3} [Fe (CN)_{6}]_{2} + 6 KCl$

TestHub · Accepted Answer

2 CuSO 4 ​ + K 4 ​ [ Fe ( CN ) 6 ​ ] CH 3 ​ COOH ​ (Chocolate brown ppt.) Cu 2 ​ [ Fe ( CN ) 6 ​ ] + 2 K 2 ​ SO 4 ​ ​ 4 FeCl 3 ​ + 3 K 4 ​ [ Fe ( CN ) 6 ​ ] ⟶ (Prussian Blue ppt.) Fe 4 ​ [ Fe ( CN ) 6 ​ ] 3 ​ ​ + 12 KCl 3 ZnCl 4 ​ + 2 K 4 ​ [ Fe ( CN ) 6 ​ ] NH 4 ​ OH ​ (White or bluish white ppt.) K 2 ​ Zn 3 ​ [ Fe ( CN ) 6 ​ ] 2 ​ ​ + 6 KCl

Chemistry - Salt Analysis Question with Solution | TestHub

Options:

Doubts & Discussion