Chemistry - Salt Analysis Question with Solution | TestHub

$\frac{2AgN{O}_3(s)\text{buildrel}\Delta }{⟶2Ag(s)+2N{O}_2(g)+O_2(g)}$

Both the ${\mathrm{NO}}_2$ and ${\mathrm{O}}_2$ gases are paramagnetic. ${\mathrm{NO}}_2\left(\mathrm{g}\right)$ has $1$ unpaired electron and ${\mathrm{O}}_2\left(\mathrm{g}\right)$ has $2$ unpaired electrons. According to MOT, electronic configuration of ${\mathrm{O}}_2$ is

${\mathrm{\sigma }}_{1\mathrm{s}}^2 \mathrm{\sigma }{*}_{1\mathrm{s}}^2 {\mathrm{\sigma }}_{2\mathrm{s}}^2 \mathrm{\sigma }{*}_{2\mathrm{s}}^2 {\mathrm{\sigma }}_{2{\mathrm{p}}_2}^2 {\mathrm{\pi }}_{2{\mathrm{p}}_{\mathrm{x}}}^2={\mathrm{\pi }}_{2{\mathrm{\lambda }}_{\mathrm{y}}}^2 \mathrm{\pi }{*}_{2{\mathrm{p}}_{\mathrm{x}}}^1=\mathrm{\pi }{*}_{2{\mathrm{\rho }}_{\mathrm{y}}}^1$

Total number of electrons present in antibonding molecular orbitals $=6$