Chemistry - Salt Analysis Question with Solution | TestHub

${\mathrm{Pb}}^{2+}$ on reaction with ${\mathrm{Cl}}^{-}$, produces white precipitate of ${\mathrm{PbCl}}_2$

${\mathrm{Pb}}^{2+}+2{\mathrm{Cl}}^{-}⟶{\mathrm{PbCl}}_2\downarrow$

This precipitate is soluble in concentrated hydrochloric acid due to formation of tetrachloroplumbate $\left(\mathrm{II}\right)$ ion

${\mathrm{PbCl}}_2\downarrow +2{\mathrm{Cl}}^{-}⟶{\left[{\mathrm{PbCl}}_4\right]}^{2-}$

On addition of potassium chromate (K2CrO4 ) solution to lead chloride a yellow precipitate of lead chromate is obtained.