20:["$","div",null,{"className":"px-6 pb-6","children":[false,["$","div",null,{"className":"text-foreground leading-relaxed mb-6","children":["$","div",null,{"className":"question-html prose dark:prose-invert max-w-none","dangerouslySetInnerHTML":{"__html":"

If the formula of basic Beryllium nitrate is $\"[\"B e_{n} O {(N O_{3})}_{6}\"]\"$ . What is the value of 'n' here

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Basic Beryllium nitrate is $\"[\"B e_{4} O {(N O_{3})}_{6}\"]\"$
$2 n - 2 - 6 = 0$
Hence, $n = 4$

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Chemistry - s Block Elements Question with Solution | TestHub

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