Chemistry - Redox Reactions Question with Solution | TestHub

The approximate mass (in g) of ${\mathrm{N}}_2{\mathrm{H}}_4$ that can be oxidized by 38.8 g of ${\mathrm{K}}_2\mathrm{Cr}{\mathrm{O}}_4$ is (Cr = 52) $3{\mathrm{N}}_2{\mathrm{H}}_4$ + $4Cr{\mathrm{O}}_4^{2-}$ + $4{\mathrm{H}}_2\mathrm{O}$ $\to$ $3{\mathrm{N}}_2$ + $\mathrm{Cr}(\mathrm{OH}{)}_4^{-}$ + $4O{\mathrm{H}}^{-}$