Chemistry - Redox Reactions Question with Solution | TestHub

Equivalents of metal nitrate = equivalents of metal sulphate. Per equivalent, the salt mass is E + 62 for the nitrate (NO₃⁻ is monovalent, 62) and E + 48 for the sulphate (SO₄²⁻ contributes 96/2 = 48 per equivalent). So 0.5/(E + 62) = 0.43/(E + 48) $\to$ 0.5E + 24 = 0.43E + 26.66 $\to$ E = 38. Atomic weight = valency x 38, so possible values are 38, 76, 114, ... ; hence A may be 76 (valency 2). Thus (a) and (c).