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Chemistry - Redox Reactions Question with Solution | TestHub

ChemistryRedox ReactionsProblem involving Equivalent ConceptMedium2 minQB

ChemistryMediumnumerical

V litre of $S O_{2}$ at 0°C and 1 atm is required to reduce 8.45 g of $HCl O_{3}$ to $HCl$ . The number of moles in '10 V' litre of $S O_{2}$ at 273°C and 4 atm is

Answer:

6.00

Solution:

$HCl O_{3}$ : 8.45/84.5 = 0.1 mol; Cl +5 $\to$ -1 needs 0.6 mol $e^{-}$ , so $S O_{2}$ = 0.3 mol and V = 0.3 × 22.4 = 6.72 L. Then 10V = 67.2 L at 273°C, 4 atm: $n$ = 4 × 67.2/0.0821 × 546 = 268.8/44.83 ≈ 6. Ans: 6.

Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Problem involving Equivalent Concept

⏱ 2mℹ️ Source: QB

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