In the reaction: C l 2 + 2NaOH → NaCl + NaClO + H 2 O (cold, dilute alkali), the equivalent weight of H 2 O is

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Chemistry - Redox Reactions Question with Solution | TestHub

ChemistryRedox ReactionsEquivalent Weight and n-factorEasy2 minQB

ChemistryEasysingle choice

In the reaction: $C l_{2}$ + 2NaOH $\to$ $NaCl$ + $NaClO$ + $H_{2} O$ (cold, dilute alkali), the equivalent weight of $H_{2} O$ is

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Solution:

$C l_{2}$ disproportionates 1:1 here: one Cl gains 1 $e^{-}$ (to $NaCl$ ), the other loses 1 $e^{-}$ (to $NaClO$ ), so 1 $e^{-}$ is transferred per 1 mol $H_{2} O$ formed. n-factor of $H_{2} O$ = 1, Eq wt = M. Hence (a).

Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Equivalent Weight and n-factor

⏱ 2mℹ️ Source: QB

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