Chemistry - Redox Reactions Question with Solution | TestHub
ChemistryRedox ReactionsEquivalent Weight and n-factorEasy2 minQB
ChemistryEasymultiple choice
A metal forms two oxides. The higher oxide contains 25% oxygen, while 4.4 g of the lower oxide when converted to higher oxide, become 4.8 g. The equivalent weight of
Options:(select one or more)
Answer:
B, D
Solution:
Higher oxide: 25% O 75% metal, so E = 8 75/25 = 24. Metal mass in the higher oxide = 0.75 4.8 = 3.6 g, so the lower oxide holds 4.4 - 3.6 = 0.8 g of oxygen, giving E(lower) = 8 3.6/0.8 = 36. Hence the lower oxide has E = 36 and the higher oxide E = 24: (b) and (d).
Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Equivalent Weight and n-factor
⏱ 2mℹ️ Source: QB
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