Chemistry - Redox Reactions Question with Solution | TestHub

In acid, KMnO₄ has n = 5, so 15.8 g = 0.1 mol = 0.5 g-eq; we need 0.5 g-eq of reductant. (a) HCl: 18.25/36.5 = 0.5 mol, n = 1 $\to$ 0.5 g-eq. (b) H₂C₂O₄: 22.5/90 = 0.25 mol, n = 2 $\to$ 0.5 g-eq. (c) SO₂: 32/64 = 0.5 mol, n = 2 $\to$ 1.0 g-eq (excess). (d) FeSO₄: 38/152 = 0.25 mol, n = 1 $\to$ 0.25 g-eq (insufficient). Exactly 0.5 g-eq comes from (a) and (b).