Cr(OH)₃ + ClO⁻ + OH⁻ → ... + Cl⁻ + H₂O. The missing ion is

In alkaline medium ClO⁻ oxidises Cr(III) to Cr(VI): 2Cr(OH)₃ + 3ClO⁻ + 4OH⁻ → 2CrO₄²⁻ + 3Cl⁻ + 5H₂O. The missing ion is CrO₄²⁻. Hence (c).

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ChemistryRedox ReactionsProblem involving Equivalent ConceptEasy2 minQB

ChemistryEasysingle choice

Cr(OH)₃ + ClO⁻ + OH⁻ $\to$ ... + Cl⁻ + H₂O. The missing ion is

Answer:

Solution:

In alkaline medium ClO⁻ oxidises Cr(III) to Cr(VI): 2Cr(OH)₃ + 3ClO⁻ + 4OH⁻ $\to$ 2CrO₄²⁻ + 3Cl⁻ + 5H₂O. The missing ion is CrO₄²⁻. Hence (c).

Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Problem involving Equivalent Concept

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