An aqueous solution containing 2.14 g KI O 3 was treated with an excess of KI solution. The solution was acidified with HCl . The liberated I 2 consumed 50 ml of thiosulphate solution to decolouri

Question

An aqueous solution containing 2.14 g KI O 3 ​ was treated with an excess of KI solution. The solution was acidified with HCl . The liberated I 2 ​ consumed 50 ml of thiosulphate solution to decolourize the blue starch-iodine complex. The molarity of the sodium thiosulphate solution is x M, then the value of 1000x is (K = 39, I = 127)

TestHub · Accepted Answer

KI O 3 ​ = 2.14/214 = 10 mmol, liberating 30 mmol I 2 ​ (1:3). Thiosulphate = 60 mmol in 50 ml, so x = 1.2 M and 1000x = 1200.

Chemistry - Redox Reactions Question with Solution | TestHub

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