Chemistry - Redox Reactions Question with Solution | TestHub
ChemistryRedox ReactionsProblem involving Equivalent ConceptMedium2 minQB
ChemistryMediumnumerical
Basic solution of Na₂XeO₆ is powerful oxidants. How many millimoles of Mn(NO₃)₂·6H₂O reacts with 62.5 ml of a 0.04 M basic solution of Na₄XeO₆ that contains an excess of sodium hydroxide if the products include Xe and a solution of sodium permanganate? (Mn = 55)
Answer:
4.00
Solution:
Moles of XeO₆⁴⁻ = 0.0625 × 0.04 = 2.5 mmol; Xe goes +8 0 (8e each), giving 20 mmol e⁻. Mn²⁺ MnO₄⁻ is +2 +7 (5e each), so Mn²⁺ = 20/5 = 4 mmol. Ans: 4.
Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Problem involving Equivalent Concept
⏱ 2mℹ️ Source: QB
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