Chemistry - Redox Reactions Question with Solution | TestHub

${\mathrm{MnO}}_4^{-}\to {\mathrm{Mn}}^{2+}n$-factor $=5$

Equivalents of ${\mathrm{MnO}}_4^{-}=1.61\times 10^{-3}\times 5=8.05\times 10^{-3}$

Equivalents of ${\mathrm{A}}^{\mathrm{n}+}=8.05\times 10^{-3}$

N -factor of ${\mathrm{AO}}_3^{-}=5-\mathrm{n}\therefore (5-\mathrm{n})\times 2.68\times 10^{-3}=8.05\times 10^{-3}$

$5-\mathrm{n}=3\mathrm{n}=2$