Chemistry - Redox Reactions Question with Solution | TestHub
ChemistryRedox ReactionsTitrationMedium2 minQB
ChemistryMediumsingle choice
Passage / Comprehension
In the presence of fluoride ion, Mn²⁺ can be titrated with MnO₄⁻, both reactants being converted to a complex of Mn(III). A 0.458 g of sample containing Mn₃O₄ was dissolved and all manganese was converted to Mn²⁺. Titration in the presence of fluoride ion consumed 30.0 ml of KMnO₄ that was 0.125 N against oxalate. (Mn = 55)
What is the percentage of Mn₃O₄ in the sample?
Options:
Answer:
A
Solution:
Against oxalate KMnO₄ has n-factor 5, so molarity = 0.125/5 = 0.025 M; moles MnO₄⁻ = 30.0 × 0.025 = 0.75 mmol. From the 4 : 1 stoichiometry, Mn²⁺ = 4 × 0.75 = 3 mmol, so Mn₃O₄ = 1 mmol. Mass = 1 × 229 mg = 0.229 g. Percentage = 0.229/0.458 × 100 = 50.00%, matching (a).
Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Titration
⏱ 2mℹ️ Source: QB
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