Chemistry - Redox Reactions Question with Solution | TestHub

${\mathrm{Cr}}_2{\mathrm{O}}_7^{2-}+14{\mathrm{H}}^{+}+6{\mathrm{e}}^{-}\to 2{\mathrm{Cr}}^{3+}+7{\mathrm{H}}_2\mathrm{O}$

${\mathrm{a}}_1=6$

${\mathrm{a}}_2=1$

${\mathrm{a}}_1=\mathrm{n}$-factor of ${\mathrm{K}}_2{\mathrm{Cr}}_2{\mathrm{O}}_7$

${\mathrm{a}}_2=\mathrm{n}$-factor of ${\mathrm{FeSO}}_4$

${\mathrm{Fe}}^{2+}\to {\mathrm{Fe}}^{3+}+{\mathrm{e}}^{-}$

$\underset{\begin{array}{c}{\mathrm{C}}_1{\mathrm{CrO}}_7{\mathrm{a}}_1=0\end{array}}{{\mathrm{a}}_1{\mathrm{M}}_1{\mathrm{V}}_1}=\underset{\begin{array}{c}\left({\mathrm{FesO}}_4\right){\mathrm{a}}_2=1\end{array}}{{\mathrm{a}}_2{\mathrm{M}}_2{\mathrm{V}}_2}$

${\mathrm{M}}_1=0.1\mathrm{M}$

${\mathrm{M}}_2=0.5\mathrm{M}$

${\mathrm{V}}_1=$ ?

${\mathrm{V}}_2=35\mathrm{mL}$

So ${\mathrm{V}}_1=\frac{1\times 0.5\times 35\mathrm{mL}}{6\times 0.1}=29.2\mathrm{mL}$