Chemistry - Redox Reactions Question with Solution | TestHub
ChemistryRedox ReactionsEquivalent Weight and n-factorMedium2 minQB
ChemistryMediumsingle choice
Passage / Comprehension
KMnO₄ oxidizes Xⁿ⁺ ion to XO₃⁻ in acid solution. 2.5×10⁻³ mole of Xⁿ⁺ requires 1.5×10⁻³ mole of MnO₄⁻.
What is the atomic mass of X, if the mass of 1 g-equivalent of XClₙ in this reaction is 56? XClₙ is the molecular form of x⁺ⁿ.
Options:
Answer:
C
Solution:
n-factor of XCl₂ in this oxidation = 3, so M(XCl₂) = 3 × 56 = 168. Atomic mass of X = 168 - 2 × 35.5 = 168 - 71 = 97, matching (c).
Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Equivalent Weight and n-factor
⏱ 2mℹ️ Source: QB
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