Chemistry - Redox Reactions Question with Solution | TestHub
ChemistryRedox ReactionsDetermination of Oxidation StateHard2 minQB
ChemistryHardmatching list
Match the oxidation number of the underlined element in Column I with the value in Column II.
Column I | Column II |
|---|---|
A) \mathrm{N̲_{2}H_{4}} | P) +1 |
B) \mathrm{H_{3}P̲O_{2}} | Q) +2 |
C) \mathrm{K_{4}[Fe(C̲N)_{6}}] | R) -2 |
D) \mathrm{S̲O_{2}} | S) +4 |
Options:
Answer:
D
Solution:
(A) In : 2x + 4 = 0 gives N = -2 (R). (B) In : 3 + - 4 = 0 gives P = +1 (P). (C) In the ligand, N = -3, so C - 3 = -1 gives C = +2 (Q). (D) In : - 4 = 0 gives S = +4 (S).
Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Determination of Oxidation State
⏱ 2mℹ️ Source: QB
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