Chemistry - Redox Reactions Question with Solution | TestHub
Match Column I with the correct volume(s) in Column II.
Column I | Column II |
|---|---|
A) Equivalent volume of Cl₂ gas | P) 5.6 L at 0°C and 1 atm |
B) Volume of O₂ needed for complete combustion of 5.6 L methane at 0°C and 1 atm | Q) 11.2 L at 0°C and 1 atm |
C) Equivalent volume of O₂ gas | R) 22.4 L at 0°C and 0.5 atm |
D) Equivalent volume of SO₂ gas as O.A. | S) 11.2 L at 0°C and 0.5 atm |
Options:
Answer:
Solution:
One equivalent is a fraction of a mole, and the same mole amount at 0°C occupies 22.4 L at 1 atm or twice that at 0.5 atm; so 1/2 mol = 11.2 L (1 atm) = 22.4 L (0.5 atm), and 1/4 mol = 5.6 L (1 atm) = 11.2 L (0.5 atm). (A) Cl₂ + 2e⁻ 2Cl⁻: 1 eq = 1/2 mol = 11.2 L at 1 atm (Q) = 22.4 L at 0.5 atm (R). (B) CH₄ + 2O₂ CO₂ + 2H₂O: 5.6 L CH₄ needs 2 x 5.6 = 11.2 L O₂ at the same T, P (Q), equally 22.4 L at 0.5 atm (R). (C) O₂ + 4e⁻ 2O²⁻: 1 eq = 1/4 mol = 5.6 L at 1 atm (P) = 11.2 L at 0.5 atm (S). (D) SO₂ as oxidizing agent: SO₂ + 4e⁻ S: 1 eq = 1/4 mol, so P and S.
