Chemistry - Salt Analysis Question with Solution | TestHub

The reaction of bismuth(III) hydroxide, $\mathrm{Bi}(\mathrm{OH}{)}_3$, with a stannite ion, $[\mathrm{Sn}(\mathrm{OH}{)}_4{]}^{2-}$, produces a black precipitate of bismuth metal, $\mathrm{Bi}$. This is a redox reaction where $\mathrm{B}{\mathrm{i}}^{3+}$ is reduced to $\mathrm{Bi}$ and $\mathrm{S}{\mathrm{n}}^{2+}$ is oxidized to $\mathrm{S}{\mathrm{n}}^{4+}$.

The balanced chemical equation is:

$$2\mathrm{Bi}(\mathrm{OH}{)}_3(\mathrm{s})+3[\mathrm{Sn}(\mathrm{OH}{)}_4{]}^{2-}(\mathrm{aq})⟶2\mathrm{Bi}(\mathrm{s})+3[\mathrm{Sn}(\mathrm{OH}{)}_6{]}^{2-}(\mathrm{aq})$$