Chemistry - Redox Reactions Question with Solution | TestHub
ChemistryRedox ReactionsBalancing of Redox ReactionsMedium2 minQB
ChemistryMediumnumerical
AO₂ disproportionates into AO₄⁻ and Aⁿ⁺ ion. If the mole ratio of AO₂ undergone oxidation and reduction is 2:3, the value of n is
Answer:
2.00
Solution:
O.S. of A in AO₂ = +4. Oxidation: AO₂ AO₄⁻ (A: +4 +7), loss of 3e per mole. Reduction: AO₂ Aⁿ⁺ (A: +4 +n), gain of (4-n)e per mole. Electron balance with 2:3 ratio: 2 × 3 = 3(4-n) ⇒ 4 - n = 2 ⇒ n = 2. Ans: 2.
Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Balancing of Redox Reactions
⏱ 2mℹ️ Source: QB
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