Chemistry - Redox Reactions Question with Solution | TestHub

${\mathrm{XCl}}_2+6{\mathrm{OH}}^{-}\to {\mathrm{ClO}}_3{}^{-}+{\mathrm{yCl}}^{-}+3{\mathrm{H}}_2\mathrm{O}$

Balancing the above reaction :

${\mathrm{Cl}}_2+6{\mathrm{H}}_2\mathrm{O}\to 2{\mathrm{ClO}}_3^{-}+12{\mathrm{H}}^{+}+10{\mathrm{e}}^{-}$ ...(1)

${\mathrm{Cl}}_2+2{\mathrm{e}}^{-}\to 2{\mathrm{Cl}}^{-}$ ...(2)

Now adding the above equation :

Eq. (1) $+5\times$ eq. (2)

$6{\mathrm{Cl}}_2+6{\mathrm{H}}_2\mathrm{O}\to 2{\mathrm{ClO}}_3^{-}+10{\mathrm{Cl}}^{-}+12{\mathrm{H}}^{+}$

dividing the above equation by 2

$3{\mathrm{Cl}}_2+3{\mathrm{H}}_2\mathrm{O}\to {\mathrm{ClO}}_3{}^{-}+5{\mathrm{Cl}}^{-}+6{\mathrm{H}}^{+}$

Now adding equal number of ${\mathrm{OH}}^{-}$in both side : $3{\mathrm{Cl}}_2+3{\mathrm{H}}_2\mathrm{O}+6{\mathrm{OH}}^{-}\to {\mathrm{ClO}}_3{}^{-}+5{\mathrm{Cl}}^{-}+6{\mathrm{H}}^{+}+6{\mathrm{OH}}^{-}$ $3{\mathrm{Cl}}_2+6{\mathrm{OH}}^{-}\to {\mathrm{ClO}}_3^{-}+5{\mathrm{Cl}}^{-}+3{\mathrm{H}}_2\mathrm{O}$

So, $\mathrm{x}=3,\mathrm{y}=5$

Now, $\mathrm{x}+\mathrm{y}=3+5=8$