How many mole of KMn O 4 is needed per mole of X n + to oxidize it to X O 3 − | TestHub

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How many mole of $KMn O_{4}$ is needed per mole of $X^{n +}$ to oxidize it to $X O_{3}^{-}$ in strong basic medium?

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Answer:

B

Solution:

In strong basic medium $Mn O_{4}^{-}$ is reduced only to $Mn O_{4}^{2 -}$ (manganate), gaining 1 $e^{-}$ per Mn. $X^{3 +}$ $\to$ $X O_{3}^{-}$ loses 2 $e^{-}$ , so 2 mol $KMn O_{4}$ are needed per mol of $X^{n +}$ , matching (b).

Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Titration

⏱ 2mℹ️ Source: QB

Chemistry - Redox Reactions Question with Solution | TestHub

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