Purple of Cassius is prepared by reducing AuC l 3 to colloidal gold by SnC l 2 . A 1 L solution containing 3.94 mg of gold per ml is prepared from 0.1 M AuC l 3 solution by reduction with approp

Question

Purple of Cassius is prepared by reducing $AuC l_{3}$ to colloidal gold by $SnC l_{2}$ . A 1 L solution containing 3.94 mg of gold per ml is prepared from 0.1 M $AuC l_{3}$ solution by reduction with appropriate amount of 0.1 M $SnC l_{2}$ solution, the resulting solution being diluted to 1 L with water. The volume of stannous chloride solution required, if its oxidation product is $SnC l_{4} (aq)$ , is (Au = 197)

Options:

Answer:

D

Solution:

Mass of Au = 3.94 g = 0.02 mol. $SnC l_{2}$ needed = 1.5 $x$ 0.02 = 0.03 mol ( $3 e^{-}$ per Au, $2 e^{-}$ per Sn). Volume of 0.1 M $SnC l_{2}$ = 0.03/0.1 = 0.3 L = 300 ml, option (d).

TestHub · Accepted Answer

Mass of Au = 3.94 g = 0.02 mol. SnC l 2 ​ needed = 1.5 x 0.02 = 0.03 mol ( 3 e − per Au, 2 e − per Sn). Volume of 0.1 M SnC l 2 ​ = 0.03/0.1 = 0.3 L = 300 ml, option (d).

Chemistry - Redox Reactions Question with Solution | TestHub

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