Chemistry - Redox Reactions Question with Solution | TestHub

Total mass$=4\mathrm{g}$

Now

$\mathrm{NaOH}:$ a mol ${\mathrm{W}}_{\mathrm{NaOH}}+{\mathrm{W}}_{{\mathrm{Na}}_2{\mathrm{CO}}_3}=4$

${\mathrm{Na}}_2{\mathrm{CO}}_3:$ $\text{'}\mathrm{a}\text{'}$ mol $\Rightarrow 40\mathrm{a}+106\mathrm{a}=4$

$\Rightarrow \mathrm{a}=\frac{4}{146} \mathrm{mol}$

$\Rightarrow$ therefore mass of $\mathrm{NaOH}$ is: $\frac{4}{146}\times 40 \mathrm{g}$

$=1.095\approx 1$