What will be the value of x, y and z in the following equation? H 2 C 2 O 4 + x H 2 O 2 → y C O 2 + z H 2 O

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(i) The half reaction for oxidation is,
$H_{2} C_{2} O_{4} \to C O_{2}$
Balancing carbon atoms on both sides, $H_{2} C_{2} O_{4} \to 2 C O_{2}$
Balancing hydrogen atoms on both sides, $H_{2} C_{2} O_{4} \to 2 C O_{2} + 2 H^{+}$
Balancing the charge on both sides,
$H_{2} C_{2} O_{4} \to 2 C O_{2} + 2 H^{+} + 2 e^{-}$ ...(i)
(ii) The half reaction for reduction is‐ $H_{2} O_{2} \to H_{2} O$
Balancing oxygen atoms on both sides, $H_{2} O_{2} \to 2 H_{2} O$
Balancing hydrogen atoms, $H_{2} O_{2} + 2 H^{+} \to 2 H_{2} O$
Balancing the charge,
$H_{2} O_{2} + 2 H^{+} + 2 e^{-} \to 2 H_{2} O$ ...(ii)
Now, adding both equations, $H_{2} C_{2} O_{4} + H_{2} O_{2} \to 2 C O_{2} + 2 H_{2} O$
This is balanced equation so x, y, z are 1,2,2 respectively.

Chemistry - Redox Reactions Question with Solution | TestHub

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