Chemistry - Redox Reactions Question with Solution | TestHub

ChemistryRedox ReactionsBalancing of Redox ReactionsEasy2 minPYQ_2020

ChemistryEasysingle choice

In redox reaction, $H_{2} O_{2}$ oxidises $K_{4} [F e (C N)_{6}]$ into $K^{+}, F e^{+ 3}, C O_{3}^{- 2}$ and $N O_{3}^{-}$ ions in acidic medium, than how many moles of $H_{2} O_{2}$ will react with $1 m o l e$ of $K_{4} [F e (C N)_{6}]$

Options:

Answer:

Solution:

$n - f a c t o r o f H_{2} O_{2} = 2$

$n - f a c t o r of K_{4} [F e (C N)_{6}] = 61$

$∵ \frac{m o l e o f H_{2} O_{2}}{1 m o l e o f K_{4} F e (C N)_{6}} = \frac{61}{2}$

$∴ m o l e of H_{2} O_{2} = \frac{61}{2} \times 1 = 30.5$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Redox ReactionsSubtopic:Balancing of Redox Reactions

⏱ 2mℹ️ Source: PYQ_2020

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