Chemistry - Redox Reactions Question with Solution | TestHub

ChemistryRedox ReactionsMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

What is the value of n in the following half equation,

${Cr(OH)}_{4}^{-} + {OH}^{-} \to {CrO}_{4}^{2 -} + H_{2} O + {ne}^{-} ?$

Options:

Answer:

Solution:

$C r (O H)_{4}^{-} + O H^{-} \to C r O_{4}^{2 -} + H_{2} O$

To balance H and O atoms, add $3 H_{2} O$ to R.H.S. and $30 H^{⊖}$ to the L.H.S. we have,

$C r (O H)_{4}^{-} + 4 O H^{-} \to C r O_{4}^{2 -} + 4 H_{2} O$

To balance charge, add $3 e^{-}$ to the R.H.S. we have

$C r (O H)_{4}^{-} + 4 O H^{-} \to C r O_{4}^{2 -} + 4 H_{2} O + 3 e^{-}$

Stream:NTA_ABHYASSubject:ChemistryTopic:Redox ReactionsSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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