Chemistry - Redox Reactions Question with Solution | TestHub

ChemistryRedox ReactionsMiscellaneous/MixedEasy2 minPYQ_2020
ChemistryEasysingle choice

2.56×10-3equivalent of KOH is required to neutralise 0.12544 g  H 2 XO 4 . The atomic mass of X (in g/mol ) is:
[Given: H 2 XO 4 is a dibasic acid]

Options:

Answer:
D
Solution:

Let the atomic weight of X = y
No. of equivalents of KOH = No. of equivalents of H 2 XO 4
i.e.0.1254466 + y2 =2.56×10-3
∴ y = 32

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Redox ReactionsSubtopic:Miscellaneous/Mixed
⏱ 2mℹ️ Source: PYQ_2020

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