In the following change, 3 F e + 4 H 2 O → F e 3 O 4 + 4 H 2 If the atomic weight of iron is 56, then its equivalent weight will be

3 F e 0 → F e 3 + ( 8 / 3 ) + 8 e - So E = M n - f a c t o r = M 8 / 3 = 56 × 3 8 = 21 .

Chemistry - Redox Reactions Question with Solution | TestHub

ChemistryRedox ReactionsMiscellaneous/MixedEasy2 minPYQ_2020

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In the following change,
$3 F e + 4 H_{2} O \to F e_{3} O_{4} + 4 H_{2}$
If the atomic weight of iron is 56, then its equivalent weight will be

Answer:

Solution:

$3 F e^{0} \to F e_{3}^{+ (8 / 3)} + 8 e^{-}$
So $E = \frac{M}{n - f a c t o r} = \frac{M}{8 / 3} = \frac{56 \times 3}{8} = 21$ .

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Redox ReactionsSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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