Chemistry - Redox Reactions Question with Solution | TestHub

no. of equivalent of acid = no of equivalent of Base

${\left(\frac{\text{W}\text{e}\text{i}\text{g}\text{h}\text{t}}{\text{M}\text{o}\text{l}\text{e}\text{c}\text{u}\text{l}\text{a}\text{r}\text{w}\text{e}\text{i}\text{g}\text{h}\text{t}}\times \text{'}\text{n}\text{'}\text{f}\text{a}\text{c}\text{t}\text{o}\text{r}\right)}_{\text{B}\text{a}\text{s}\text{e}}={\left(\text{N}\times {\text{V}}_{\text{l}\text{i}\text{t}\text{e}\text{r}}\right)}_{\text{A}\text{c}\text{i}\text{d}}$

$\therefore$n factor of NaOH = 1

$\therefore$n factor of Oxalic acid = 1

$1=\frac{\text{x}\times 1000}{63\times 100}\text{x}=6.3\text{g}\text{m}\text{s}$