Chemistry - Real Gas Question with Solution | TestHub
ChemistryReal GasLiquification & Critical Constants of GasesMedium2 minQB
ChemistryMediumsingle choice
Passage / Comprehension
The equation of state for one mole of a gas is: P = RT/(V − b) − a/(T·V²), where V is the molar volume and a and b are constants different from van der Waals constants.
The temperature above which the gas cannot be liquefied at any pressure is
Options:
Answer:
B
Solution:
At the critical point (partial P/partial V)T = 0 gives RT²V³ = 2a(V-b)² and (partial²P/partial V²)T = 0 gives RT²V⁴ = 3a(V-b)³. Dividing, Vc = 3b; substituting back, RTc²(3b)³ = 2a(2b)², so Tc = √(8a/27Rb). Above this temperature liquefaction is impossible. Hence Ans (b).
Stream:JEESubject:ChemistryTopic:Real GasSubtopic:Liquification & Critical Constants of Gases
⏱ 2mℹ️ Source: QB
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