Chemistry - Real Gas Question with Solution | TestHub
ChemistryReal GasVander Waal's Gas EquationMedium2 minQB
ChemistryMediummultiple choice
Van der Waal's constant 'a' can be expressed as
Options:(select one or more)
Answer:
A, B, D
Solution:
From Vc = 3b, Pc = a/27b2, Tc = 8a/27Rb: (b) 3PcVc2 = 3·(a/27b2)·9b2 = a ✓; (a) (9/8)RTcVc = (9/8)R·(8a/27Rb)·3b = a ✓; (d) (27/64)R2Tc2/Pc = (27/64)R2·(64a2/729R2b2)/(a/27b2) = a ✓. (c) (3/8)(PcVc/Tc) = (3/8)(3R/8) = 9R/64, which is not a. Hence (a), (b), (d).
Stream:JEESubject:ChemistryTopic:Real GasSubtopic:Vander Waal's Gas Equation
⏱ 2mℹ️ Source: QB
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