Chemistry - Real Gas Question with Solution | TestHub
ChemistryReal GasCompressibility FactorHard2 minQB
ChemistryHardnumerical
The density of a gas (in g/litre) depends on pressure (in atm) at 300 K as:
d = 4P + 0.02P2 + 0.001P3 + …
The molar mass of gas (in g/mol) is (R = 0.08 l-atm/K-mol)
Answer:
96.00
Solution:
For a real gas, d/P = M/(RT) only in the limit P → 0 (ideal limit); the higher-order terms describe non-ideality. Divide the series by P: d/P = 4 + 0.02P + 0.001P2 + ..., so lim(P→0) d/P = 4 g/L-atm. Then M = (lim d/P) × RT = 4 × 0.08 × 300 = 96 g/mol. Hence the molar mass is 96 g/mol.
Stream:JEESubject:ChemistryTopic:Real GasSubtopic:Compressibility Factor
⏱ 2mℹ️ Source: QB
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