Chemistry - Real Gas Question with Solution | TestHub

From the graph, above 31.1°C (critical temperature), CO₂ cannot be liquefied; therefore, A is false.

At $T<31.1$°C, complete liquefaction is possible on compression; thus, B is correct.

Path A→C→E→D shows a gas → liquid transition with a flat region (two-phase equilibrium), so C is correct.

At critical point E, ${\left(\frac{\partial P}{\partial V}\right)}_T=0$and ${\left(\frac{{\partial }^{2}P}{\partial V^2}\right)}_T=0$

the gas and liquid phases become indistinguishable; thus, D is correct.