Chemistry - Real Gas Question with Solution | TestHub
ChemistryReal GasVander Waal's Gas EquationMedium2 minQB
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van der Waal's constant a and b for a gas are 4.0 atm l2/mol2 and 0.05 l/mol, respectively. If 80 g of the gas (molecular mass = 16) is placed in a 10 l vessel at 300 K, then
Column I | Column II |
|---|---|
A) Pressure correction (in atm) | P) 0.0625 |
B) Ideal volume of gas (in L) | Q) 1 |
C) Actual volume occupied by molecules (in L) | R) 9.75 |
D) Volume correction (in L) | S) 0.25 |
Options:
Answer:
D
Solution:
n = 80/16 = 5 mol, V = 10 L. Pressure correction = an2/V2 = 4.0 × 25/100 = 1 atm (A→Q). Volume correction (excluded volume) = nb = 5 × 0.05 = 0.25 L (D→S). Ideal (free) volume = V - nb = 10 - 0.25 = 9.75 L (B→R). Since b = 4 × actual molecular volume per mole, actual volume occupied by molecules = nb/4 = 0.25/4 = 0.0625 L (C→P). Hence A→Q; B→R; C→P; D→S.
Stream:JEESubject:ChemistryTopic:Real GasSubtopic:Vander Waal's Gas Equation
⏱ 2mℹ️ Source: QB
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