Chemistry - Ideal Gas Question with Solution | TestHub

Isothermal curves follow the equation $PV=constant$, and a higher curve on the graph corresponds to a higher temperature.

In the graph, the $T_2$ curve lies above $T_1$, which means $T_2>T_1$.

Using $T_1=\frac{PV}{nR}=\frac{1\times 20.8}{1\times 0.0831}\approx 250\mathrm{K}$ and $T_2=\frac{PV}{nR}=\frac{1\times 41.6}{1\times 0.0831}\approx 500\mathrm{K}$ (n = 1 mol, R = 0.0831 bar L mol⁻¹ K⁻¹).

Therefore, $T_1=250K$ and $T_2=500K$