A rigid container containing 10 gm gas at some pressure and temperature. The gas has been allowed to escape (do not consider any effusion or diffusion) from the container due to which pressure of the

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A rigid container containing 10 gm gas at some pressure and temperature. The gas has been allowed to escape (do not consider any effusion or diffusion) from the container due to which pressure of the gas becomes half of its initial pressure and temperature become

(2/3)^{rd}

of its initial. The mass of gas (in gms) escaped is

TestHub · Accepted Answer

PV = M 10 ​ RT Let x gm of the gas remain in the flask when final press 2 P ​ , 3 2 T ​ . ∴ ( 2 P ​ ) V = ( M x ​ ) R ( 3 2 T ​ ) ​ ( 2 ) ​ (1) / (2) ⇒ 2 = x w ​ × 2 3 ​ ⇒ 4 x = 3 w x = 4 3 × 10 ​ So, the amount of gas escape is = 10 − 4 3 × 10 ​ = 4 10 ​ = 2 5 ​

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