The pressure of mixture of equal weights of two gases of molecular weight 4 and 40 is 1.1 atm .
The partial pressure of the lighter gas in the gas mixture is

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The pressure of mixture of equal weights of two gases of molecular weight 4 and 40 is 1.1 atm . The partial pressure of the lighter gas in the gas mixture is

TestHub · Accepted Answer

Let x gm each gas be present in the mixture Mole of lighter gas

= \frac{x}{4} = 0.25 x

Mole of heavier gas

= \frac{x}{40} = 0.025 x

Total no. of moles

= 0.25 x + 0.025 x = 0.0275 x

Let P , be the partial pressure of tuhe lighter gas

P_{1} = (\frac{Moles}{Total moles}) \times Total press. = \frac{6.25 \times 1.1}{0.275} = 1 atm .]

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