Chemistry - PRACTICAL ORGANIC CHEMISTRY Question with Solution | TestHub

(A) Chloroform $+$ Aniline $\to$ $\mathrm{III}$ Distillation

(B) Benzoic acid $+$ Napthalene $\to \mathrm{IV}$ Crystallisation

(C) Water $+$ Aniline $\to \mathrm{I}$ Steam distillation

(D) Napthalene $+$ Sodium chloride $\to \mathrm{II}$ Sublimation

Aniline is purified using the process of steam distillation because aniline is steam volatile and it is insoluble in water.

Chloroform and aniline having boiling points $334 \mathrm{K}$ and $457 \mathrm{K}$ can be separated by distillation. More volatile chloroform vaporizes first and is collected in the receiver. Aniline is left in the distillation flask.

Benzoic acid is soluble in hot water but naphthalene is not soluble, hence separation can be carried out by hot water crystallisation.

Naphthalene can also be separated by sublimation from non-volatile at room temperature.

The vapor of naphthalene can be collected and solidified.