Chemistry - PRACTICAL ORGANIC CHEMISTRY Question with Solution | TestHub

ChemistryPRACTICAL ORGANIC CHEMISTRYELEMENTAL ANALYSISMedium2 minPYQ_2022

ChemistryMediumsingle choice

$0.20 g$ of an organic compound gave $0.12 g$ of AgBr By using Carius method, the percentage of bromine in the compound will be

Options:

Answer:

Solution:

Given, Mass of an organic compound $= 0.20 g$ Mass of $AgBr = 0.12 g$ Molecular mass of $AgBr = 188 g mol^{- 1}$ $188 g$ of AgBr contains $80 g$ of bromine $∴ 0.12 g$ of $AgBr$ will contain $= \frac{80}{188} \times 0.12$ $= 0.05 g$ of bromine $∴$ Percentage of bromine $= \frac{0.05}{0.20} \times 100$ $= 25%$

Stream:BITSATSubject:ChemistryTopic:PRACTICAL ORGANIC CHEMISTRYSubtopic:ELEMENTAL ANALYSIS

⏱ 2mℹ️ Source: PYQ_2022

Doubts & Discussion

Loading discussions...